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3n^2+9n+4.75=180
We move all terms to the left:
3n^2+9n+4.75-(180)=0
We add all the numbers together, and all the variables
3n^2+9n-175.25=0
a = 3; b = 9; c = -175.25;
Δ = b2-4ac
Δ = 92-4·3·(-175.25)
Δ = 2184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2184}=\sqrt{4*546}=\sqrt{4}*\sqrt{546}=2\sqrt{546}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-2\sqrt{546}}{2*3}=\frac{-9-2\sqrt{546}}{6} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+2\sqrt{546}}{2*3}=\frac{-9+2\sqrt{546}}{6} $
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